a=2(.5)/0.32^2

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Solution for a=2(.5)/0.32^2 equation: 



a=2(.5)/0.32^2

We move all terms to the left:

a-(2(.5)/0.32^2)=0

We add all the numbers together, and all the variables

a-(2(0.5)/0.32^2)=0

We multiply all the terms by the denominator


a*0.32^2)-(2(0.5)=0

Wy multiply elements

0a^2=0

We add all the numbers together, and all the variables

a^2=0

a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$a=\frac{-b}{2a}=\frac{0}{2}=0$

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